x^2-(29/10)x+1=0

Solution for x^2-(29/10)x+1=0 equation:

x^2-(29/10)x+1=0


Domain of the equation: 10)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

x^2-(+29/10)x+1=0

We multiply parentheses

x^2-29x^2+1=0

We add all the numbers together, and all the variables

-28x^2+1=0

a = -28; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·(-28)·1
Δ = 112
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{112}=\sqrt{16*7}=\sqrt{16}*\sqrt{7}=4\sqrt{7}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{7}}{2*-28}=\frac{0-4\sqrt{7}}{-56}
=-\frac{4\sqrt{7}}{-56}
=-\frac{\sqrt{7}}{-14}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{7}}{2*-28}=\frac{0+4\sqrt{7}}{-56}
=\frac{4\sqrt{7}}{-56}
=\frac{\sqrt{7}}{-14}
$